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"""
This program print the matix in spiral form.
This problem has been solved through recursive way.
Matrix must satisfy below conditions
i) matrix should be only one or two dimensional
ii)column of all the row should be equal
"""
def checkMatrix(a):
# must be
if type(a) == list and len(a) > 0:
if type(a[0]) == list:
prevLen = 0
for i in a:
if prevLen == 0:
prevLen = len(i)
result = True
elif prevLen == len(i):
result = True
else:
result = False
else:
result = True
else:
result = False
return result
def spiralPrint(a):
if checkMatrix(a) and len(a) > 0:
matRow = len(a)
if type(a[0]) == list:
matCol = len(a[0])
else:
for dat in a:
print(dat),
return
# horizotal printing increasing
for i in range(0, matCol):
print(a[0][i]),
# vertical printing down
for i in range(1, matRow):
print(a[i][matCol - 1]),
# horizotal printing decreasing
if matRow > 1:
for i in range(matCol - 2, -1, -1):
print(a[matRow - 1][i]),
# vertical printing up
for i in range(matRow - 2, 0, -1):
print(a[i][0]),
remainMat = [row[1 : matCol - 1] for row in a[1 : matRow - 1]]
if len(remainMat) > 0:
spiralPrint(remainMat)
else:
return
else:
print("Not a valid matrix")
return
# driver code
a = [[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12]]
spiralPrint(a)