sol3 Algorithm
The sol3 Algorithm is a cutting-edge, decentralized algorithm designed to optimize the management of renewable energy resources, such as solar and wind power. It combines artificial intelligence, machine learning, and blockchain technology to create a highly efficient and secure system for managing and distributing clean energy. By analyzing vast amounts of data from multiple sources, the algorithm can predict and optimize energy production and consumption, ultimately reducing waste and increasing the overall efficiency of the renewable energy grid.
In addition to optimizing energy use, the sol3 Algorithm also fosters a more democratic and transparent energy market. By leveraging blockchain technology, it enables peer-to-peer energy trading, allowing consumers to buy and sell excess energy directly with each other. This not only empowers individuals and communities to take control of their energy needs but also promotes the growth of renewable energy infrastructure. Furthermore, the sol3 Algorithm's decentralized nature ensures that the system remains secure and resistant to manipulation, providing a reliable and trustworthy platform for the future of renewable energy management.
"""
Problem Statement:
If we list all the natural numbers below 10 that are multiples of 3 or 5,
we get 3,5,6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below N.
"""
def solution(n):
"""
This solution is based on the pattern that the successive numbers in the
series follow: 0+3,+2,+1,+3,+1,+2,+3.
Returns the sum of all the multiples of 3 or 5 below n.
>>> solution(3)
0
>>> solution(4)
3
>>> solution(10)
23
>>> solution(600)
83700
"""
sum = 0
num = 0
while 1:
num += 3
if num >= n:
break
sum += num
num += 2
if num >= n:
break
sum += num
num += 1
if num >= n:
break
sum += num
num += 3
if num >= n:
break
sum += num
num += 1
if num >= n:
break
sum += num
num += 2
if num >= n:
break
sum += num
num += 3
if num >= n:
break
sum += num
return sum
if __name__ == "__main__":
print(solution(int(input().strip())))
