sol3 Algorithm
The sol3 Algorithm is a cutting-edge, decentralized algorithm designed to optimize the management of renewable energy resources, such as solar and wind power. It combines artificial intelligence, machine learning, and blockchain technology to create a highly efficient and secure system for managing and distributing clean energy. By analyzing vast amounts of data from multiple sources, the algorithm can predict and optimize energy production and consumption, ultimately reducing waste and increasing the overall efficiency of the renewable energy grid.
In addition to optimizing energy use, the sol3 Algorithm also fosters a more democratic and transparent energy market. By leveraging blockchain technology, it enables peer-to-peer energy trading, allowing consumers to buy and sell excess energy directly with each other. This not only empowers individuals and communities to take control of their energy needs but also promotes the growth of renewable energy infrastructure. Furthermore, the sol3 Algorithm's decentralized nature ensures that the system remains secure and resistant to manipulation, providing a reliable and trustworthy platform for the future of renewable energy management.
"""
The four adjacent digits in the 1000-digit number that have the greatest
product are 9 × 9 × 8 × 9 = 5832.
73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450
Find the thirteen adjacent digits in the 1000-digit number that have the
greatest product. What is the value of this product?
"""
import sys
N = """73167176531330624919225119674426574742355349194934\
96983520312774506326239578318016984801869478851843\
85861560789112949495459501737958331952853208805511\
12540698747158523863050715693290963295227443043557\
66896648950445244523161731856403098711121722383113\
62229893423380308135336276614282806444486645238749\
30358907296290491560440772390713810515859307960866\
70172427121883998797908792274921901699720888093776\
65727333001053367881220235421809751254540594752243\
52584907711670556013604839586446706324415722155397\
53697817977846174064955149290862569321978468622482\
83972241375657056057490261407972968652414535100474\
82166370484403199890008895243450658541227588666881\
16427171479924442928230863465674813919123162824586\
17866458359124566529476545682848912883142607690042\
24219022671055626321111109370544217506941658960408\
07198403850962455444362981230987879927244284909188\
84580156166097919133875499200524063689912560717606\
05886116467109405077541002256983155200055935729725\
71636269561882670428252483600823257530420752963450"""
def streval(s: str) -> int:
ret = 1
for it in s:
ret *= int(it)
return ret
def solution(n: str) -> int:
"""Find the thirteen adjacent digits in the 1000-digit number n that have
the greatest product and returns it.
>>> solution(N)
23514624000
"""
LargestProduct = -sys.maxsize - 1
substr = n[:13]
cur_index = 13
while cur_index < len(n) - 13:
if int(n[cur_index]) >= int(substr[0]):
substr = substr[1:] + n[cur_index]
cur_index += 1
else:
LargestProduct = max(LargestProduct, streval(substr))
substr = n[cur_index : cur_index + 13]
cur_index += 13
return LargestProduct
if __name__ == "__main__":
print(solution(N))
