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"""
Problem:
Comparing two numbers written in index form like 2'11 and 3'7 is not difficult, as any calculator would confirm that 2^11 = 2048 < 3^7 = 2187.
However, confirming that 632382^518061 > 519432^525806 would be much more difficult, as both numbers contain over three million digits.
Using base_exp.txt, a 22K text file containing one thousand lines with a base/exponent pair on each line, determine which line number has the greatest numerical value.
NOTE: The first two lines in the file represent the numbers in the example given above.
"""
import os
from math import log10
def find_largest(data_file: str = "base_exp.txt") -> int:
"""
>>> find_largest()
709
"""
largest = [0, 0]
for i, line in enumerate(open(os.path.join(os.path.dirname(__file__), data_file))):
a, x = list(map(int, line.split(",")))
if x * log10(a) > largest[0]:
largest = [x * log10(a), i + 1]
return largest[1]
if __name__ == "__main__":
print(find_largest())