stack using dll Algorithm

The stack using a doubly linked list (DLL) algorithm is a dynamic data structure that stores a collection of elements in a linear fashion, where each element has a reference to the element before and after it. This stack allows for the efficient management of elements by performing insertions and deletions at the beginning or end of the list without affecting the rest of the elements. A commonly used analogy to describe a stack is a stack of plates, where you can only add or remove a plate from the top of the stack. This behavior is known as Last-In, First-Out (LIFO), which means that the most recently added element is always the first one to be removed. Implementing a stack using a doubly linked list offers several advantages over other data structures like arrays. First, it allows for dynamic resizing, which means that the stack can grow or shrink in size as elements are added or removed. This makes it more memory-efficient, as the stack only uses the exact amount of memory needed to store its elements. Second, the time complexity for inserting and deleting elements in a DLL-based stack is O(1), which makes these operations quite fast. However, this comes at the cost of increased complexity in managing the pointers for the previous and next elements in the list, which can make the implementation more challenging than using an array-based stack.
# A complete working Python program to demonstrate all
# stack operations using a doubly linked list


class Node:
    def __init__(self, data):
        self.data = data  # Assign data
        self.next = None  # Initialize next as null
        self.prev = None  # Initialize prev as null


class Stack:
    """
    >>> stack = Stack()
    >>> stack.is_empty()
    True
    >>> stack.print_stack()
    stack elements are:
    >>> for i in range(4):
    ...     stack.push(i)
    ...
    >>> stack.is_empty()
    False
    >>> stack.print_stack()
    stack elements are:
    3->2->1->0->
    >>> stack.top()
    3
    >>> len(stack)
    4
    >>> stack.pop()
    3
    >>> stack.print_stack()
    stack elements are:
    2->1->0->
    """

    def __init__(self):
        self.head = None

    def push(self, data):
        """add a Node to the stack"""
        if self.head is None:
            self.head = Node(data)
        else:
            new_node = Node(data)
            self.head.prev = new_node
            new_node.next = self.head
            new_node.prev = None
            self.head = new_node

    def pop(self):
        """pop the top element off the stack"""
        if self.head is None:
            return None
        else:
            temp = self.head.data
            self.head = self.head.next
            self.head.prev = None
            return temp

    def top(self):
        """return the top element of the stack"""
        return self.head.data

    def __len__(self):
        temp = self.head
        count = 0
        while temp is not None:
            count += 1
            temp = temp.next
        return count

    def is_empty(self):
        return self.head is None

    def print_stack(self):
        print("stack elements are:")
        temp = self.head
        while temp is not None:
            print(temp.data, end="->")
            temp = temp.next


# Code execution starts here
if __name__ == "__main__":

    # Start with the empty stack
    stack = Stack()

    # Insert 4 at the beginning. So stack becomes 4->None
    print("Stack operations using Doubly LinkedList")
    stack.push(4)

    # Insert 5 at the beginning. So stack becomes 4->5->None
    stack.push(5)

    # Insert 6 at the beginning. So stack becomes 4->5->6->None
    stack.push(6)

    # Insert 7 at the beginning. So stack becomes 4->5->6->7->None
    stack.push(7)

    # Print the stack
    stack.print_stack()

    # Print the top element
    print("\nTop element is ", stack.top())

    # Print the stack size
    print("Size of the stack is ", len(stack))

    # pop the top element
    stack.pop()

    # pop the top element
    stack.pop()

    # two elements have now been popped off
    stack.print_stack()

    # Print True if the stack is empty else False
    print("\nstack is empty:", stack.is_empty())

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